def sortByWordCount(ls: list[str]) -> None:
    """
    Sort ls in place by word count.
    """
    
    def wordCount(x: str) -> int:
        """
        Return the number of words in the string x.
        """
        #help(x.split)
        print(x.split())
        return len(x.split())
    
    ls.sort(key=wordCount)
    
x = ["a lot of short words", "few magniloquent words"]
sortByWordCount(x)
print(x)

['a', 'lot', 'of', 'short', 'words']
['few', 'magniloquent', 'words']
['few magniloquent words', 'a lot of short words']

lst = [12]
s = "Hello"

#help(sortByWordCount)
#help(lst.reverse)
#help(lst.index)
#print(12 in lst)
#print(lst.index(12))
#help(s.join)
#print("".join(["a", "b", "c"]))
#help(s.split)
#help(s.find)
#print(s.find("lo"))
help(lst.index)

Help on built-in function index:

index(value, start=0, stop=9223372036854775807, /) method of builtins.list instance
    Return first index of value.
    
    Raises ValueError if the value is not present.

info = {
    "surname": "Richards",
    #"surname": "Kenneth",
    "given name": "Gregor",
    "height": 1.76,
    "employer": "University of Waterloo",
    "alma mater": "Purdue University",
    "graduation year": 2014,
    "employment years": 11,
    42: 12
}

print(
    info[42], info["surname"]
)
print(info)

12 Kenneth
{'surname': 'Kenneth', 'given name': 'Gregor', 'height': 1.76, 'employer': 'University of Waterloo', 'alma mater': 'Purdue University', 'graduation year': 2014, 'employment years': 11, 42: 12}

info["employment years"] = 12
print(info)

{'surname': 'Kenneth', 'given name': 'Gregor', 'height': 1.76, 'employer': 'University of Waterloo', 'alma mater': 'Purdue University', 'graduation year': 2014, 'employment years': 12, 42: 12}

info = {
    "surname": "Richards",
    "given name": "Gregor",
    "height": 1.76,
    "employer": "University of Waterloo",
    "alma mater": "Purdue University",
    "graduation year": 2014,
    "employment years": 11
}

for x in info:
    print(x, "is", info[x])
    
lst = list(info)
print(lst)

surname is Richards
given name is Gregor
height is 1.76
employer is University of Waterloo
alma mater is Purdue University
graduation year is 2014
employment years is 11
['surname', 'given name', 'height', 'employer', 'alma mater', 'graduation year', 'employment years']

info = {
    "surname": "Richards",
    "given name": "Gregor",
    "height": 1.76,
    "employer": "University of Waterloo",
    "alma mater": "Purdue University",
    "graduation year": 2014,
    "employment years": 11
}

#print(info["citizenship"])
info["citizenship"] = ["USA"]
print(info["citizenship"])
print(info["surname"])
print(info)

#info["last name"] = info["surname"]

if "age" in info:
    print("This person is", info["age"], "years old")
    
info.pop("employer") # Fired for tormenting Science students
print(info["employer"])

['USA']
Richards
{'surname': 'Richards', 'given name': 'Gregor', 'height': 1.76, 'employer': 'University of Waterloo', 'alma mater': 'Purdue University', 'graduation year': 2014, 'employment years': 11, 'citizenship': ['USA']}

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
Input In [43], in <cell line: 23>()
     20     print("This person is", info["age"], "years old")
     22 info.pop("employer") # Fired for tormenting Science students
---> 23 print(info["employer"])

KeyError: 'employer'

import typing

def distribution(
    lst: typing.Sequence
) -> dict[typing.Any, int]:
    """
    Returns the distribution of values in lst, as a dictionary associating each *value* in the
    list with its count.
    """
    ret: dict[typing.Any, int] = {}
    for val in lst:
        #if val not in ret:
        if not (val in ret):
            ret[val] = 0
        ret[val] = ret[val] + 1
    return ret

print(distribution([
    8, 6, 7, 5, 3, 0, 9, 2, 4, 6, 0, 1
]))
print(distribution("It was the best of times, it was the worst of times"))

{8: 1, 6: 2, 7: 1, 5: 1, 3: 1, 0: 2, 9: 1, 2: 1, 4: 1, 1: 1}
{'I': 1, 't': 8, ' ': 11, 'w': 3, 'a': 2, 's': 6, 'h': 2, 'e': 5, 'b': 1, 'o': 3, 'f': 2, 'i': 3, 'm': 2, ',': 1, 'r': 1}

def distributionChart(lst: typing.Sequence) -> None:
    """
    Prints a distribution chart of the frequency of each value in the sequence lst.
    """
    dist = distribution(lst)
    for key in sorted(dist):
        print(key, "*" * dist[key])
        
distributionChart([8, 6, 7, 5, 3, 0, 9, 2, 4, 6, 0, 1])
distributionChart("It was the best of times, it was the worst of times")

0 **
1 *
2 *
3 *
4 *
5 *
6 **
7 *
8 *
9 *
  ***********
, *
I *
a **
b *
e *****
f **
h **
i ***
m **
o ***
r *
s ******
t ********
w ***

def distributionChart(lst: typing.Sequence) -> None:
    """
    Prints a distribution chart of the frequency of each value in the sequence lst.
    """
    dist = distribution(lst)
    
    def appearances(key: typing.Any) -> int:
        """
        Return the number of times that the value key appears in the list lst.
        """
        return dist[key]
    
    for key in sorted(dist, key=appearances, reverse=True):
        print(key, "*" * dist[key])
        
distributionChart([8, 6, 7, 5, 3, 0, 9, 2, 4, 6, 0, 1])
distributionChart("It was the best of times, it was the worst of times")

6 **
0 **
8 *
7 *
5 *
3 *
9 *
2 *
4 *
1 *
  ***********
t ********
s ******
e *****
w ***
o ***
i ***
a **
h **
f **
m **
I *
b *
, *
r *

annoying = {}
annoying[0.3-0.2] = "Hello"
annoying[0.1] = "world"
print(annoying)

{0.09999999999999998: 'Hello', 0.1: 'world'}