This chapter presents the second case study, which involves solving word puzzles by searching for words that have certain properties. For example, we’ll find the longest palindromes in English and search for words whose letters appear in alphabetical order. And I will present another program development plan: reduction to a previously solved problem.
For the exercises in this chapter we need a list of English words. There are lots of word lists available on the Web, but the one most suitable for our purpose is one of the word lists collected and contributed to the public domain by Grady Ward as part of the Moby lexicon project (see http://wikipedia.org/wiki/Moby_Project). It is a list of 113,809 official crosswords; that is, words that are considered valid in crossword puzzles and other word games. In the Moby collection, the filename is 113809of.fic; you can download a copy, with the simpler name words.txt, from http://thinkpython2.com/code/words.txt.
This file is in plain text, so you can open it with a text editor, but you can also read it from Python. The built-in function open takes the name of the file as a parameter and returns a file object you can use to read the file.
fin is a common name for a file object used for input. The file object provides several methods for reading, including readline, which reads characters from the file until it gets to a newline and returns the result as a string:
The first word in this particular list is “aa”, which is a kind of
lava. The sequence \n
represents the newline character that
separates this word from the next.
The file object keeps track of where it is in the file, so if you call readline again, you get the next word:
The next word is “aah”, which is a perfectly legitimate word, so stop looking at me like that. Or, if it’s the newline character that’s bothering you, we can get rid of it with the string method strip:
You can also use a file object as part of a for loop. This program reads words.txt and prints each word, one per line:
There are solutions to these exercises in the next section. You should at least attempt each one before you read the solutions.
Write a program that reads words.txt and prints only the words with more than 20 characters (not counting whitespace).
In 1939 Ernest Vincent Wright published a 50,000 word novel called Gadsby that does not contain the letter “e”. Since “e” is the most common letter in English, that’s not easy to do.
In fact, it is difficult to construct a solitary thought without using that most common symbol. It is slow going at first, but with caution and hours of training you can gradually gain facility.
All right, I’ll stop now.
Write a function called has_no_e
that returns True if
the given word doesn’t have the letter “e” in it.
Write a program that reads words.txt and prints only the words that have no “e”. Compute the percentage of words in the list that have no “e”.
Write a function named avoids that takes a word and a string of forbidden letters, and that returns True if the word doesn’t use any of the forbidden letters.
Write a program that prompts the user to enter a string of forbidden letters and then prints the number of words that don’t contain any of them. Can you find a combination of 5 forbidden letters that excludes the smallest number of words?
Write a function named uses_only
that takes a word and a
string of letters, and that returns True if the word contains
only letters in the string. Can you make a sentence using only the
letters acefhlo? Other than “Hoe alfalfa”?
Write a function named uses_all
that takes a word and a
string of required letters, and that returns True if the word
uses all the required letters at least once. How many words are there
that use all the vowels aeiou? How about aeiouy?
Write a function called is_abecedarian
that returns
True if the letters in a word appear in alphabetical order
(double letters are ok).
How many abecedarian words are there?
All of the exercises in the previous section have something in common; they can be solved with the search pattern we saw in Section 15.2. The simplest example is:
The for loop traverses the characters in word. If we find the letter “e”, we can immediately return False; otherwise we have to go to the next letter. If we exit the loop normally, that means we didn’t find an “e”, so we return True.
You could write this function more concisely using the in operator, but I started with this version because it demonstrates the logic of the search pattern.
avoids is a more general version of has_no_e
but it
has the same structure:
We can return False as soon as we find a forbidden letter; if we get to the end of the loop, we return True.
uses_only
is similar except that the sense of the condition
is reversed:
Instead of a string of forbidden letters, we have a string of available letters. If we find a letter in word that is not in available, we can return False.
uses_all
is similar except that we reverse the role
of the word and the string of letters:
Instead of traversing the letters in word, the loop traverses the required letters. If any of the required letters do not appear in the word, we can return False.
If you were really thinking like a computer scientist, you would
have recognized that uses_all
was an instance of a
previously solved problem, and you would have written:
This is an example of a program development plan called reduction to a previously solved problem, which means that you recognize the problem you are working on as an instance of a solved problem and apply an existing solution.
I wrote the functions in the previous section with for loops because I only needed the characters in the strings; I didn’t have to do anything with the indices.
For is_abecedarian
we have to compare adjacent letters,
which is a little tricky with a for loop:
An alternative is to use recursion:
Another option is to use a while loop:
The loop starts at i=0 and ends when i=len(word)-1. Each time through the loop, it compares the th character (which you can think of as the current character) to the th character (which you can think of as the next).
If the next character is less than (alphabetically before) the current one, then we have discovered a break in the abecedarian trend, and we return False.
If we get to the end of the loop without finding a fault, then the
word passes the test. To convince yourself that the loop ends
correctly, consider an example like ’flossy’
. The
length of the word is 6, so
the last time the loop runs is when i is 4, which is the
index of the second-to-last character. On the last iteration,
it compares the second-to-last character to the last, which is
what we want.
Here is a version of is_palindrome
that uses two indices; one starts at the
beginning and goes up; the other starts at the end and goes down.
Or we could reduce to a previously solved problem and write:
Testing programs is hard. The functions in this chapter are relatively easy to test because you can check the results by hand. Even so, it is somewhere between difficult and impossible to choose a set of words that test for all possible errors.
Taking has_no_e
as an example, there are two obvious
cases to check: words that have an ‘e’ should return False, and
words that don’t should return True. You should have no
trouble coming up with one of each.
Within each case, there are some less obvious subcases. Among the words that have an “e”, you should test words with an “e” at the beginning, the end, and somewhere in the middle. You should test long words, short words, and very short words, like the empty string. The empty string is an example of a special case, which is one of the non-obvious cases where errors often lurk.
In addition to the test cases you generate, you can also test your program with a word list like words.txt. By scanning the output, you might be able to catch errors, but be careful: you might catch one kind of error (words that should not be included, but are) and not another (words that should be included, but aren’t).
In general, testing can help you find bugs, but it is not easy to generate a good set of test cases, and even if you do, you can’t be sure your program is correct. According to a legendary computer scientist:
Program testing can be used to show the presence of bugs, but never to show their absence!
— Edsger W. Dijkstra
A value that represents an open file.
A way of solving a problem by expressing it as an instance of a previously solved problem.
A test case that is atypical or non-obvious (and less likely to be handled correctly).
This question is based on a Puzzler that was broadcast on the radio program Car Talk (http://www.cartalk.com/content/puzzlers):
Give me a word with three consecutive double letters. I’ll give you a couple of words that almost qualify, but don’t. For example, the word committee, c-o-m-m-i-t-t-e-e. It would be great except for the ‘i’ that sneaks in there. Or Mississippi: M-i-s-s-i-s-s-i-p-p-i. If you could take out those i’s it would work. But there is a word that has three consecutive pairs of letters and to the best of my knowledge this may be the only word. Of course there are probably 500 more but I can only think of one. What is the word?
Write a program to find it.
Here’s another Car Talk Puzzler (http://www.cartalk.com/content/puzzlers):
“I was driving on the highway the other day and I happened to notice my odometer. Like most odometers, it shows six digits, in whole miles only. So, if my car had 300,000 miles, for example, I’d see 3-0-0-0-0-0.
“Now, what I saw that day was very interesting. I noticed that the last 4 digits were palindromic; that is, they read the same forward as backward. For example, 5-4-4-5 is a palindrome, so my odometer could have read 3-1-5-4-4-5.
“One mile later, the last 5 numbers were palindromic. For example, it could have read 3-6-5-4-5-6. One mile after that, the middle 4 out of 6 numbers were palindromic. And you ready for this? One mile later, all 6 were palindromic!
“The question is, what was on the odometer when I first looked?”
Write a Python program that tests all the six-digit numbers and prints any numbers that satisfy these requirements.
Here’s another Car Talk Puzzler you can solve with a search (http://www.cartalk.com/content/puzzlers):
“Recently I had a visit with my mom and we realized that the two digits that make up my age when reversed resulted in her age. For example, if she’s 73, I’m 37. We wondered how often this has happened over the years but we got sidetracked with other topics and we never came up with an answer.
“When I got home I figured out that the digits of our ages have been reversible six times so far. I also figured out that if we’re lucky it would happen again in a few years, and if we’re really lucky it would happen one more time after that. In other words, it would have happened 8 times over all. So the question is, how old am I now?”
Write a Python program that searches for solutions to this Puzzler. Hint: you might find the string method zfill useful.